131.25=w^2+10w

Solution for 131.25=w^2+10w equation:

131.25=w^2+10w

We move all terms to the left:

131.25-(w^2+10w)=0

We get rid of parentheses

-w^2-10w+131.25=0

We add all the numbers together, and all the variables

-1w^2-10w+131.25=0

a = -1; b = -10; c = +131.25;
Δ = b2-4ac
Δ = -102-4·(-1)·131.25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-25}{2*-1}=\frac{-15}{-2}
=7+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+25}{2*-1}=\frac{35}{-2}
=-17+1/2
$